Re: qw(l i s t) vs (l, i, s, t)

Tor Hildrum wrote:
> 
> Not sure if this belongs here, but anyway:
> 
> [hildrum:~] tor% perl -e '@ARGV = qw(1 2); if(scalar(@ARGV)==qw(2 3) )
> {print "yes\n"}'
> yes
> [hildrum:~] tor%
> 
> [hildrum:~] tor% perl -e '@ARGV = qw(1 2); if(scalar(@ARGV)==(2, 3) )
> {print "yes\n"}'
> [hildrum:~] tor%
> 
> &&
> 
> [hildrum:~] tor% perl -e '@ARGV = qw(1 2 3); if(scalar(@ARGV)==(2, 3) )
> {print "yes\n"}'
> yes
> [hildrum:~] tor%
> 
> [hildrum:~] tor% perl -e '@ARGV = qw(1 2 3); if(scalar(@ARGV)==qw(2 3) )
> {print "yes\n"}'
> [hildrum:~] tor%

What version of perl are you using? On 5.6.0 and 5.8.0 the first two are false
for me (as I'd expect).

Although thinking about it, qw doesn't have a comma anywhere, so why would it
use the comma operator to return the last element? That wouldn't make much
sense. Would it?

I have no idea. I don't know why I'm bothering to add my 2 pennies worth.

Jasper
-- 
Lloyd Christmas: Excuse me, miss, what's the soup du jour?
Waitress:        The Soup of the Day.
Lloyd Christmas: Mmmm...sounds good, think I'll have that.