Re: Processing list

Dear all,
I have difficulty processing a list a Scala:
Currently I have a list of like this

(List(JString(2437), JString(2445), JString(2428), JString(321)), CompactBuffer((4,1)))

and I would like after processing, the result will look like below:

( (2437, CompactBuffer((4,1))), (2445, CompactBuffer((4,1))), (2428, CompactBuffer((4,1))), (321, CompactBuffer((4,1))) )

I have got a helpful reply but I am still got stuck when I try this


val pair = (List(JString(2437), JString(2445), JString(2428), JString(321)), CompactBuffer((4,1)))val result = pair._1.map((_, pair._2))

First, pair._1 gets the list from the tuple. Then, map performs the 
function on each element of the list. The function (_, pair._2) puts the 
given element from the list in a new tuple together with the second part of 
the pair tuple.


I got an error:
value _1 is not a member of org.apache.spark.rdd.RDD[(String, Array[(Int, 
Int)])]. 

It seems that List(JString(2437), JString(2445), JString(2428), JString(321
)) is a string rather than a list. Can anybody help me with that?

Thank you very much.




Vào 18:21:17 UTC+7 Thứ Tư, ngày 07 tháng 10 năm 2015, Kim Trang Le đã viết:
>
> Dear all, I have difficulty processing a list a scala:
> Currently I have a list of like this
>
> (List(JString(2437), JString(2445), JString(2428), JString(321)), 
> CompactBuffer((4,1)))
>
> and I would like after processing, the result will look like below:
>
> ( (2437, CompactBuffer((4,1))) ,  (2445, CompactBuffer((4,1))) , (2428, 
> CompactBuffer((4,1))), (321, CompactBuffer((4,1))) )
>
> Can any body help me with this issue? 
> Thank you very much.
>

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