Re: Converting Fortran 90 array access to use Matrix?

Does subrange not do what you want?

<snippet... it should be mostly readable...>

  (...input matrix a of size nxn )

  int n = a.size2();
  int size = 2*n;

  boost::numeric::ublas::matrix<double>p(size,size);

  boost::numeric::ublas::subrange(p, 0,n,    0,n)    = -trans(a);
  boost::numeric::ublas::subrange(p, 0,n,    n,size) = ublas::zero_matrix<double>(n,n);
  boost::numeric::ublas::subrange(p, n,size, 0,n)    = temp * dt;
  boost::numeric::ublas::subrange(p, n,size, n,size) = a;


Bob the amateur.

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What is the most efficient way to convert Fortran's column array access
like shown below to C++?

a(i,:) = 0 ! set entire column to zero



I suspect best solution might use matrix proxies like matrix_row?

Can this be done on one line without the for loop?

Can you help me fix the syntax on the commented out code that attempted
to use iterators?