Re: Converting Fortran 90 array access to use Matrix?

Good answer! I didn't realize from the nerdy / cryptic documentation
pages that subrange could be used on the LHS (an L-value). When this
project is over, I really should collect up a few examples and post them
for boost ublas newbies on how to use the library. The current
documentation assumes more of a computer science / linear algebra PhD
background. Anyway, once you get it, more fun that C arrays.

I promote you to Bob the advanced beginner IMHO. I was looking in the
right place but close only counts in horseshoes...

Thanks!
Darrell the rookie apprentice

-----Original Message-----
From: Hartley, Bob [mailto:[email protected]] 
Sent: Thursday, January 09, 2014 9:49 AM
To: [email protected]
Subject: Re: [ublas] Converting Fortran 90 array access to use Matrix?

Does subrange not do what you want?

<snippet... it should be mostly readable...>

  (...input matrix a of size nxn )

  int n = a.size2();
  int size = 2*n;

  boost::numeric::ublas::matrix<double>p(size,size);

  boost::numeric::ublas::subrange(p, 0,n,    0,n)    = -trans(a);
  boost::numeric::ublas::subrange(p, 0,n,    n,size) =
ublas::zero_matrix<double>(n,n);
  boost::numeric::ublas::subrange(p, n,size, 0,n)    = temp * dt;
  boost::numeric::ublas::subrange(p, n,size, n,size) = a;


Bob the amateur.

________________________________________


What is the most efficient way to convert Fortran's column array access
like shown below to C++?

a(i,:) = 0 ! set entire column to zero



I suspect best solution might use matrix proxies like matrix_row?

Can this be done on one line without the for loop?

Can you help me fix the syntax on the commented out code that attempted
to use iterators?