Re: Calibrating Buffer Size and Count
Kip Warner <[email protected]>
| Newsgroups | gmane.comp.lib.openal |
|---|---|
| Message-ID | <[email protected]> |
On Fri, 2010-05-28 at 13:29 -0700, Chris Robinson wrote: > A "frame size", in this case, is the size of a single sample multiplied by the > channel count (ie. channels * bits / 8; which would be 4 for 16-bit stereo, or > 1 for 8-bit mono, for example). A "buffer size" would be the size of a given > buffer (typically in bytes, but sometimes it may be measured in frames or even > time). > > So, for instance, you would generate 4 to 8 buffers, and fill them each with > frequency/4*channels*bits/8 bytes (where frequency, channels, and bits are > taken from the stream data format that's given to OpenAL): The 4 in the divisor, is that the number of buffers one chose to generate? How do I determine the number of buffers to use for a stream? Do you reckon to just hardcode it at, say, 8, and instead leave the size of the buffers themselves as the parameter to fiddle with? > int framesize = stream->channels * stream->bits / 8; > BytesPerBuffer = stream->Freq / 4 * framesize; The 4 again in the divisor is the number of buffers chosen for the stream? > When queued onto a source, the buffers should give a total play time of one to > two seconds before it all runs out, and approximately 1/4th of a second > between each buffer. Very helpful Chris. I've made a note of that in my notes. PS If you remember, please cc me so I get it faster than the batch mode dispatches. -- Kip Warner -- Software Engineer OpenPGP encrypted/signed mail preferred http://www.thevertigo.com _______________________________________________ Openal mailing list [email protected] http://opensource.creative.com/mailman/listinfo/openal
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