Re: I don't find the solution ...

Bill Allombert <[email protected]> Sun, 4 Dec 2022 10:33:08 +0100

Newsgroups	gmane.comp.mathematics.pari.devel
Message-ID	<Y4xpVMVOVJb6vxM3@seventeen>

On Sun, Dec 04, 2022 at 02:02:57AM +0100, Jean-Luc ARNAUD wrote:
> Hi,
> 
> Working with eval, I get the expected result with:
> 
> Â Â Â  eval([ a=((6*k)!*(-1)^k)/(((3*k)!*(k!)^3)*640320^(3*k)), k*a ]);
> 
> But I don't achieve the same calculation with pareval.

You cannot do this computation in parallel, simply because
you cannot compute k*a before having computed a.

Cheers,
Bill.