Re: transformToFragment with a node

Thanks for your reply, Jonas.
I tried that before and that does make sense, but it did not work.

Alex

alex iskold
founder & ceo
http://www.adaptiveblue.com


"Jonas Sicking" <[email protected]> wrote in message 
news:[email protected]...
> Alex Iskold wrote:
>> Hi all,
>>
>> I am trying to do the following:
>>
>> JavaScript
>>
>>     var elements = xml.documentElement.childNodes;
>>     for ( var i = start; i <= end ; i++ ) {
>>         var fragment = xsltProcessor.transformToFragment( elements[i], 
>> doc );
>>         list.appendChild( fragment );
>>     }
>>
>> XSL
>>
>> <xsl:stylesheet version="1.0"
>>   xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>>   xmlns="http://www.mozilla.org/keymaster/gatekeeper/there.is.only.xul">
>>
>> <xsl:include href="common.xsl"/>
>>
>> <xsl:output method="xml"/>
>>
>> <xsl:template match="/">
>>      <vbox>
>>     <xsl:value-of select="name(.)"/>
>>     </vbox>
>> </xsl>
>>
>> Basically, I am looping through and applying stylesheet to invididual 
>> nodes.
>>
>> But it does not seem to match, instead I get text clumped together in 
>> return.
>> I am declaring the XUL namespace so I am not sure what is wrong.
>
> Your match expression match="/" only matches root nodes in the document 
> you are transforming. However none of the nodes you are passing in are 
> root nodes, but rather elements in the middle of the document. If you 
> change your template to say
>
> <xsl:template match="*">
>
> it'll match any element that you pass in.
>
> Hope that makes sense.
>
> / Jonas