Thanks for the effort !!!

Hi Anuj;
Thanks alot for your marvellous idea,it was great !!
I couldn't imagine that i would solve it,but of course with your help 
i did it.
I really appreciate.......Infact while trying to solve it i got 
another idea which was quite interesting
...ideas produce ideas...I learnt alot in this experiment.Once again 
thanks alot.
This is your idea
// Decimal-Binary convertion
#include<iostream.h>
int main()
{
	while(1){
int memory[100]; // Array of holding data
int number;
int copy_number; // A copy of the integer (for another task)
int remainder;
cout<<"Enter an Integer :";
cin>>number;
copy_number=number;
cout<<number<<" when converted to binary,it becomes:";
for(int i=0;copy_number>0;i++){  // 1st task (knowing the number of 
bits)
	copy_number/=2;
}
i--;
int index=i;
while(number>0){        // 2nd task (calculation)
remainder=number%2;
memory[index]=remainder;
number/=2;
index--;
}
index++;
for(index;index<=i;index++){
cout<<memory[index];
}
cout<<endl;
	}
return 0;
}

It worked tremendously.
Based on that i thought another way.....

// Decimal-Binary Conversion (10 bit ?)
#include<iostream.h>
#include <math.h>
int main()
{
while(1){	
long decimal;
long binary=0; // initial sum

cout<<"Enter an Integer :";
cin>>decimal;
cout<<decimal<<",when converted to binary,it becomes :";
for(int i=0;decimal!=0;i++)// indices of the digits
{
   long firstDigit=decimal%2;
   binary+=firstDigit*long(pow(10,i));// reverses the digits and finds 
their place values
   decimal /=2; 
	
		}
cout<<binary;
cout<<endl<<endl;		
}


	return 0;
}

but with this,it has some limitations,it only solves a maximum of 10 
bit number.I really dont know why.Please help me sort it out.
Kind regards.Hashim



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