Re: using variant_dir but strip out the variant_dir from source files

I finally implemented something like _concat() so I can use it
directly in the COMSTR definition to strip out the additional path.
However now scons trying to be very verbose and every single
os.chdir() is being printed (chdir="..." used for all builders). Is
there a way to disable this os.chdir() print message without modifying
the scons source code? Thanks.
On Wed, Oct 17, 2018 at 9:55 PM Hua Yanghao <[email protected]> wrote:
>
> Dear Scons User,
> I am having maybe an odd request. The background is there are some
> compilers out there produces all kinds of output in your current
> directory which you do not have control. I wanted to combine the
> variant_dir feature plus the chdir kw arguments to builders, to be
> able to invoke those compilers directly inside the variant_dir. And I
> still want to keep the source duplication in the variant_dir as it
> will be a snapshot of only the used files for a particular built out
> of thousands of irrelevant files. As a side effect now the source
> files are all prefixed with the variant_dir which becomes "invalid"
> because the compiler is already invoked in the variant_dir instead of
> the top level directory.
>
> Is there a way (e.g. a special env variable) already that when I write
> my builders instead of "$COMPILER $SOURCE", I can use something like
> "$COMPILER $ORIGINAL_SOURCE"? Or do I have to wrap around the
> $COMPILER with another command such that I can do things like
> "$COMPILER_WRAPPED $VARIANT_DIR $SOURCE"? I know the second one
> definitely can work but wondering if there are better ways already in
> scons.
>
> Best Regards,
> Yanghao
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