Re: Once again - Object of type x...

Thank you Chris.  I'll get all these changes made and repost soon...

Peter

> -----Original Message-----
> From: Discussion relating to the specifics of the C# and
> Managed C++ languages [mailto:[email protected]]
> On Behalf Of Chris Anderson
> Sent: Monday, December 18, 2006 4:30 PM
> To: [email protected]
> Subject: Re: [DOTNET-CX] Once again - Object of type x...
>
> Only if they need to be used at design-time. Otherwise simply
> stop using them at design-time based on the this.DesignMode checks.
>
> > -----Original Message-----
> > From: Discussion relating to the specifics of the C# and
> Managed C++
> > languages [mailto:[email protected]] On Behalf Of Peter
> > Osucha
> > Sent: 18 December 2006 21:16
> > To: [email protected]
> > Subject: Re: [DOTNET-CX] Once again - Object of type x...
> >
> > OK.  So the 'nested' user controls - although the concept
> still seems
> a
> > bit
> > strange - is not necessarily a bad idea.  However, the
> classes those
> > controls use ought to be split out to a separate project.
> >
> > Peter
> >
> > > -----Original Message-----
> > > From: Discussion relating to the specifics of the C# and
> Managed C++
> > > languages [mailto:[email protected]]
> > > On Behalf Of Chris Anderson
> > > Sent: Monday, December 18, 2006 3:36 PM
> > > To: [email protected]
> > > Subject: Re: [DOTNET-CX] Once again - Object of type x...
> > >
> > > > > This is the generally recommended approach.
> > > > > If you get into a habit of checking this.DesignMode it
> > > stops a lot
> > > > > of unexpected problems (and helps to stop the IDE feeling
> > > sluggish
> > > > > as it runs runtime code (possibly trying to access
> > > databases, etc!))
> > > >
> > > > How will this (or better yet, will it at all) help the
> > > situation where
> > > > the project has 'nested' controls?
> > >
> > > The "in-design" usercontrols and their nested controls
> will not be
> > > communicating with each other (at least they will not be passing
> > > user classes between each other) because that code will be hidden
> > > behind a check for DesignMode and will therefore not be executed.
> > >
> > > Chris

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