Re: Better? or less good?

Hi Jean-Michel: the determination that "Gor" is a free variable
happens as part of the compilation of the program, much in the same
way that this expression:

  (or #t (lambda x))

is rejected.

Robby


On Fri, Oct 21, 2016 at 9:12 AM, Jean-Michel HUFFLEN
<jmhuffle-qPpMuP/[email protected]> wrote:
>    Dear Racket users,
>
>    I noticed that Racket detects the variables used without any value. But
> let us consider the expression:
>
> (or #t Gor)
>
>    Since "or" evaluates as few arguments as possible, the result is #t, but
> this expression is rejected by Racket because "Gor" is unbound. So the rule
> would become: some arguments of "and" and "or" may be not evaluated, for
> example:
>
> (and #f (/ 0))
>
> but do not use this feature with unbound identifiers... From my modest point
> of view, that is not homogeneous... What do you think, please?
>
>    Cheers,
>
> J.-M. Hufflen
>
>
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