Re: Please HELP ME
John W <[email protected]> Tue, 16 Aug 2011 21:42:40 +1200 (NZST)
| Newsgroups | gmane.science.chemistry.the-chemistry-cluster |
|---|---|
| Message-ID | <[email protected]> |
In that case, there will be no chemical reaction at all. Depending on the concentrations of the aqueous KNO3 and H2SO4, all that will happen is that the potassium aluminium alum, KAl(SO4)2.xH2O, will dissolve, yielding an acid mixture in solution of hydrated K+, Al+++, H+, NO3-, and SO4-- ions. John W. --- On Tue, 16/8/11, vahab nazeri <[email protected]> wrote: From: vahab nazeri <[email protected]> Subject: Re: [The Chemistry Cluster] Please HELP ME To: [email protected] Date: Tuesday, 16, August, 2011, 9:36 PM thank youI meaned the Alum = potassium and Aluminum sulfates --- On Mon, 8/15/11, John W <[email protected]> wrote: From: John W <[email protected]> Subject: Re: [The Chemistry Cluster] Please HELP ME To: [email protected] Date: Monday, August 15, 2011, 9:06 PM What do you mean by "Alum"? If you mean the metal, it will dissolve, giving a mixture of nitrate and sulfate in solution. John W. --- On Tue, 16/8/11, VAHAB <[email protected]> wrote: From: VAHAB <[email protected]> Subject: [The Chemistry Cluster] Please HELP ME To: [email protected] Date: Tuesday, 16, August, 2011, 12:10 AM Dear All Hi I want to know the products of this reactions KNO3+ H2SO4+ Alum = ? [email protected] thanks a lot [Non-text portions of this message have been removed] ------------------------------------ Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/thechemistrycluster/ <*> Your email settings: Individual Email | Traditional <*> To change settings online go to: http://groups.yahoo.com/group/thechemistrycluster/join (Yahoo! ID required) <*> To change settings via email: [email protected] [email protected] <*> To unsubscribe from this group, send an email to: [email protected] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/