Re: [PHP-DB]how to handle exception in php

Dear Bavithra,

I would suggest you the following solution 

$sql = "SELECT x FROM y";
$rs  = mysql_query ($sql)
$num = mysql_numrows($rs);
while ($i < $num){
	z = mysql_result($rs, $i, 'x');
	$i++;
}

I hope that above solution  help you.

Luiz Alberto


On Sun, 2010-05-02 at 10:56 +0530, Bavithra R wrote:
> hi friends
> 
> I am doing a simple student mark details project.
> for calculating rank I need to compare the total marks one by one.
> To do so i use *for loop.* so atlast while reaching the end of the table it
> shows the following warning.
> *
> Warning*: mysql_result()
> [function.mysql-result<http://127.0.0.1/pro/function.mysql-result>]:
> Unable to jump to row 18 on MySQL result index on line *50*
> 
> It is because it has no next value to compare.How to use try..catch
> exception handling in this.?Or any other suggestion.
> Can anybody help me
> 
> --Bavithra