Re: [PHP-DB]how to handle exception in php

On 02/05/10 15:26, Bavithra R wrote:
> hi friends
>
> I am doing a simple student mark details project.
> for calculating rank I need to compare the total marks one by one.
> To do so i use *for loop.* so atlast while reaching the end of the table it
> shows the following warning.
> *
> Warning*: mysql_result()
> [function.mysql-result<http://127.0.0.1/pro/function.mysql-result>]:
> Unable to jump to row 18 on MySQL result index on line *50*
>
> It is because it has no next value to compare.How to use try..catch
> exception handling in this.?Or any other suggestion.
> Can anybody help me

This isn't an exception, so a try catch won't work. (Exceptions are 
fatal and would say something like "uncaught exception ...").

This is a warning about trying to read something that doesn't exist from 
mysql.

I'd do something like

$query = "select blah";
$result = mysql_query($query);
while ($row = mysql_fetch_assoc($result)) {
   echo "do stuff here";
}

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