Re: Another problem (sorry ;-) )
[email protected] Fri, 17 Sep 1999 15:11:54 +0100
| Newsgroups | perl.riscos |
|---|---|
| Message-ID | <[email protected]> |
> > opendir (SOH,"."); # you do not need the 's around the soh, and "." is > > "here" on unix > So how would I list a subdirectory defined by $soh, ie the hardware or > software directory? If $soh contains just a directory name that will work, but remember that "." is where the script is run and that "/......" is the system root not the web root, so if $soh starts with a "/" you will need to do some surgery on the full name to convert it to an appropriate path. Hope that helps. Richard Proctor (Still at work for another hour)