Re: Another problem (sorry ;-) )

In article <[email protected]>,
   <[email protected]> wrote:



> > > opendir (SOH,"."); # you do not need the 's around the soh, and "." is
> > > "here" on unix

> > So how would I list a subdirectory defined by $soh, ie the hardware or
> > software directory?

> If $soh contains just a directory name that will work, but remember that
> "." is where the script is run and that "/......" is the system root not
> the web root, so if $soh starts with a "/" you will need to do some surgery
> on the full name to convert it to an appropriate path.

the URL is going to be http://www.<myURL>.com/script.pl?soh=hardware

This is interpretted correctly by the script (to check I just got it to output
the value)

So, how do I get the script to list the contents of the $soh directory?

I've tried using opendir (SOH,"./$sto") but that didn't work (of cource)
Denis Howe suggested using $_ = $0;  , but this doesn' seem to have any
effect, so I tried (SOH,"$_/$sto") but that doesn't work either.

> Hope that helps.

Sort of ;-)

> Richard Proctor (Still at work for another hour)

TTFN
Nik (still at home for the rest of the day :-/ )

-- 
[email protected]
http://www.cheddarcheese.webprovider.com
( http://www.cheddarcheese.de when my provider lets me use perl scripts )