Re: Funny loop with post-increment.

On Feb 19, 2008 8:01 PM, Brady Kelly <[email protected]> wrote:
> Ryan:
>
> > The feature that the returned value of i++ is i and not i+1.
>
> I've always accepted that as a given, it's just in this situation I thought
> i would be assigned i, not i+1, then i would be incremented, not i
> incremented and pre-i++ assigned back to i.

it's not "pre" i++. it happens after that. i is equal to the result of
the expression "i++". what you are missing is that i++ in that
expression doesn't actually affect the end result of "i" (even though
it is calculated) because it's overwritten.

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